chetan2u wrote:
The class teacher divided 100 pencils amongst five students, A, B, C, D and E. The number of pencils received by A is equal to the sum of the pencils received by the three students, C, D and E. It is also known\( a \geq b \geq c\geq d \geqe\) , where a, b, c, d and e are pencils received by A, B, C, D and E respectively.
On the basis of the information provided, select for MaxA-B , the maximum difference between the number of the pencils received by A and the number of the pencils received by B, and select forMin B the least number of the pencils that B could have got. Make only two selections, one in eachcolumn.
We know a = c+d+e, and a+b+c+d+e = 100 or a+b+a = 100, that is2a+b=100
Max A-B: We are looking into the difference of the two largest numbers, that is a-b. To make it the largest, we have to make a the largest possible and b the smallestpossible.
The smallest value of b will be when it is equal to c, and c is also leastpossible.
Now, c+d+e = a
For c to be least,
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Statistics : Posted by chetan2u • on 01 May 2024, 10:37 • Replies 1 • Views 129
