iakashp wrote:
"Post subject: Re: A couple decides to have 5 children. Each child is equally likely to b Post Posted: 21 Sep 2021, 21:10
In my opinion the probability will be (1/2^5)=1/32
Can someone please explain why the order is considered ?"
- You need to consider the arrangement of 3B and 2G, they can be arranged in 5!/(3!*2!) or 10 times. So 10*(1/32)=5/16.
Hello sujoykrdatta
IMO 5/16. But my reasoning is flawed.
My Process was like:
1st select 3 girls out of 5 students (remaining will be boys) then arrange them in 5!/3!*2!
but my answer is coming around 100/32 (>1 which is not possible)
So I marked E ( assumed I must have taken 10 extra, but I am not able to figure out how)
Can you please explain?
Statistics : Posted by thr3at • on 11 Sep 2021, 07:57 • Replies 10 • Views 6210
