Let their respective salaries be j & k. Where j>k
Difference in 1998 = j-k
Difference in 2000=1.03^2 (j-k)
let j-k is some variable a
Increase in difference = a(1.03^2-1^2) ........use a^2-b^2 = (a+b)(a-b)
=a*2.03*0.03
So % increase= ((2.03*0.03a)/a)*100= 6.09
Difference in 1998 = j-k
Difference in 2000=1.03^2 (j-k)
let j-k is some variable a
Increase in difference = a(1.03^2-1^2) ........use a^2-b^2 = (a+b)(a-b)
=a*2.03*0.03
So % increase= ((2.03*0.03a)/a)*100= 6.09
Statistics : Posted by mayankdgmat • on 02 Jul 2023, 07:28 • Replies 8 • Views 7546