Amobnc wrote:
Bunuel wrote:
Jan and 5 of his friends sold candy bars to raise money for their school trip. Jan sold 20 bars and each of his 5 friends sold at least onebar . Did Jan sell more candy bars than each of at least 3 of hisfriends?
(1) The median of the number of bars sold by Jan's 5 friends is 18 --> {a, b, 18, c, d}, so at least 3 friends sold less than 20 bars (a, b and 18). Sufficient.
(2) The average (arithmetic mean) of the number of bars sold by Jan's 5 friends is 12 --> total number of bars sold by Jan's 5 friends is 5*12=60. Can there be a case where at least 3 of Jan's friends sold 20 or more bars? No, since in this case the total number of bars sold by his friends would be more than 60 (20+20+20+1+1=62). Sufficient.
Answer:D.
(1) The median of the number of bars sold by Jan's 5 friends is 18 --> {a, b, 18, c, d}, so at least 3 friends sold less than 20 bars (a, b and 18). Sufficient.
(2) The average (arithmetic mean) of the number of bars sold by Jan's 5 friends is 12 --> total number of bars sold by Jan's 5 friends is 5*12=60. Can there be a case where at least 3 of Jan's friends sold 20 or more bars? No, since in this case the total number of bars sold by his friends would be more than 60 (20+20+20+1+1=62). Sufficient.
Answer:D.
Hi Bunuel,
The question asked is if Jan sold more candy bars than each of at least 3 of his friends:
In statement 2. I analyzed the following situations:
12+12+12+12+12=60 which would render a NO answer; and
1+1+12+23+23=60 which would render
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Statistics : Posted by Bunuel • on 27 Nov 2012, 00:03 • Replies 3 • Views 6713
