Sajjad1994 wrote:
A certain corporation has software that calculates the cost of a meeting. The software multiplies the hourly salary for each employee attending the meeting by the number of hours that the employee spends at the meeting. The cost of the meeting is the sum of those results. One manager has used another method to calculate the cost of a meeting. The manager takes the average (arithmetic mean) salary of all employees attending the meeting multiplied by the average number of hours that employees spend at the meeting, which is then multiplied by the total number of employees attending themeeting.
Let the employees be\( E_1,E_2\) and\(E_3\) with salary as\( S_1,S_2\) and\(S_3\) respectively and hours spent be\( H_1,H_2\) and\(H_3\).
Software : Cost of meeting= \(S_1*H_1+S_2*H_2+S_3*H_3\)
Manager : Cost of meeting= \(\frac{S_1+S_2+S_3}{3}*\frac{H_1+H_2+H_3}{3}*3\)
Both costs are equal=>
\(\frac{S_1+S_2+S_3}{3}*\frac{H_1+H_2+H_3}{3}*3\)=\(S_1*H_1+S_2*H_2+S_3*H_3\)
\(\frac{S_1+S_2+S_3}{3}*(H_1+H_2+H_3)\)=\(S_1*H_1+S_2*H_2+S_3*H_3\)
When the
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Statistics : Posted by chetan2u • on 16 Oct 2023, 08:21 • Replies 6 • Views 2072