avinashvpec wrote:
Gonaives wrote:
Why does this problem depend so much on the values tested? Is there something I am missing? Because if I use n=4 or n=7, even D is divisible by 3. Is there some hidden insight for how to approach this problem?
I agree with you, by using different values of n, all equations can be satisfied as multiple of 3.
Can someone pleaseclarify?
You should read a question more carefully. The question asks mMAY be which of the following? NOT m MUST be which of the following? We know that m is NOT a multiple
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