Same method as others have posted - but just to avoid fractions, we could take the age of eldest as a multiple of 2 & 3 both.
Let age of first person = 6x,
then age of second person = 3x
and age of third person = 2x
Sum = 6x+3x+2x = 33
Solve to get x=3. Thus age of youngest = 2x = 2*3 = 6.
hence answer is B
Let age of first person = 6x,
then age of second person = 3x
and age of third person = 2x
Sum = 6x+3x+2x = 33
Solve to get x=3. Thus age of youngest = 2x = 2*3 = 6.
hence answer is B










