BrainLab wrote:
A bag contains 4 red, 4 green and 4 white balls. Three balls are picked up one by one without replacement. What is the probability that there will be at least one red ball ?
a) 41/55
b) 3/64
c) 40/55
d) 41/50
e) 42/55
Source:PerfectScrore
[Reveal] Spoiler:
\(1-\frac{8}{12}*\frac{7}{11}*\frac{6}{10}*1\)
We could also apply the complementary probability rule (1-P) to combinatorics and solve
1-(8c2)/(10c2) - I personally find this faster than
Btwchetan2u
With the alternative method 1- (8/12)(7/11)(6/10) why is it that we cannot simplify
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