Bunuel wrote:
Algebraicapproach:
(1) n is not divisible by 2. Insufficient on its own, but this statement says that\(n=odd\) -->\(n-1\) and\(n+1\) are consecutive even integers -->\((n-1)(n+1)\) must be divisible by 8 (as both multiples are even and one of them will be divisible by 4. From consecutive even integers one is divisible by 4: (2, 4); (4, 6); (6, 8); (8, 10); (10, 12), ...).
(2) n is not divisible by 3. Insufficient on its own, but form this statement either\(n-1\) or\(n+1\) must be divisible by 3 (as\(n-1\) ,\(n\) , and\(n+1\) are consecutive integers, so one of them must be divisible by 3, we are told that it's not\(n\) , hence either\(n-1\) or\(n+1\) ).
(1)+(2) From (1)\((n-1)(n+1)\) is divisible by 8, from (2) it's also divisible by 3, therefore it must be divisible by\(8*3=24\) , which means that remainder upon division\((n-1)(n+1)\) by 24 will be 0. Sufficient.
Answer: C.
Hope it'sclear.
Hi Bunuel, With statement 1, if we assume n = 1, then, why can we still assume that n is a multiple of 8, when we solve together?
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Statistics : Posted by TargetMBA007 • on 21 Jan 2012, 16:57 • Replies 19 • Views 122176








