Bunuel wrote:
The length of a certain rectangle is 4 inches longer than its width. If the area of the rectangle is 221 square inches, then the length of the rectangle’s diagonal, in inches, is
(A) between 19 and 20
(B) between 20 and 21
(C) between 21 and 22
(D) between 22 and 23
(E) between 23 and 24
Kudos for a correct solution.
W* (w+4)= 221
221 has four factors 1, 13, 17,and liself
W= 13
length= 13 +4 = 17
According to , Pythagorean theoram
C^2= a^2 + b^2
C^2= 13^2+ 17^2
thus Diagonal could be
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