Anu2021 wrote:
Can someone share the answer to this?
Difference between A's time to reach bottom and B's time to reach bottom must be greater than 10s for B to reach first ( else A does so ), since B is released 10s later it needs to make up for the extra time lost.
Let: Ta --> time taken by a, Tb --> time taken by b, a is speed of a
1. Ta - Tb = 100/a - 100/a(a + 1) = 100/a(a + 1) --> this must be greater than 10s for B to reach faster, but for that we need to know speed of a
2. Ta - Tb = 100/a - 400/5a --> this must be greater than 10s for B to reach faster but again we need the value of a ( speed of a to check this )
Togather the statements are insufficient since if we know spped of B is 1 ft/s more than A's speed then:
1ft/s = 1/4a , then we know the value of a and can easily solve which reaches faster
Statistics : Posted by sachi-in • on 02 Nov 2023, 01:31 • Replies 3 • Views 551