Bunuel wrote:
SOLUTION
If m is an integer such that \((-2)^{2m} = 2^{9 - m}\), then m=
(A) 1
(B) 2
(C) 3
(D) 4
(E) 6
First of all, since m is an integer, then 2m=even, and therefore \((-2)^{2m}=2^{2m}\).
Sol, we have that \(2^{2m} = 2^{9 - m}\) --> \(2m=9-m\) --> \(m=3\).
Answer: C.
Bunuel
What if 'm' was a proper or improper fraction, would it still work?
Statistics : Posted by SlowTortoise • on 14 Mar 2014, 03:23 • Replies 14 • Views 20816








