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Problem Solving (PS) | If m is an integer such that (-2)^2m = 2^{9 - m}, then m=

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Bunuel wrote:

SOLUTION

If m is an integer such that \((-2)^{2m} = 2^{9 - m}\), then m=

(A) 1
(B) 2
(C) 3
(D) 4
(E) 6

First of all, since m is an integer, then 2m=even, and therefore \((-2)^{2m}=2^{2m}\).

Sol, we have that \(2^{2m} = 2^{9 - m}\) --> \(2m=9-m\) --> \(m=3\).

Answer: C.


Bunuel

What if 'm' was a proper or improper fraction, would it still work?

Statistics : Posted by SlowTortoise • on 14 Mar 2014, 03:23 • Replies 14 • Views 20816



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