Bunuel wrote:
The average (arithmetic mean) of six numbers is 24. If the sum of four of these numbers is 96, what is the average of the other 2 numbers?
A. 12
B. 24
C. 48
D. 72
E. 96
\(Σ_6 = 24*6 = 144\)
\(Σ_4 = 96\)
Thus, \(Σ_2 = Σ_6 - Σ_4\)
Or, \(Σ_2 = 144 - 96 = 48\)
Hence, Avg of \(2\) Nos will be \(\frac{48}{2} = 24\), Answer must be (B)
Statistics : Posted by Abhishek009 • on 31 Jul 2019, 09:35 • Replies 4 • Views 3637