Bunuel wrote:
For which of the following values of k can \((k + 10)x^2 + (k + 10)x – 9 = 0\) have equal roots?
I. -46
II. -10
III. 46
A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III
For the roots to be equal, the determinant should be zero. For a quadratic equation represented in the form \(ax^2 + bx + c \), the determinant is given by\( b^2 - 4ac\).
For the given equation, the determinant is \((k + 10)^2 - [4 (k+10) * (-9)]\)
\((k + 10)^2 +36 (k+10) = 0\)
\((k + 10)( k + 10 +36 ) = 0\)
\((k + 10)( k + 46 ) = 0\)
The value of k cannot be -10, as the quadratic equation will not hold true for k = -10.
Hence, k = -46
Option A
Statistics : Posted by gmatophobia • on 20 Sep 2023, 04:30 • Replies 1 • Views 110








