Sarabjeets746 wrote:
ashutoshbarawkar wrote:
If abc ≠ 0, is a < b < c ?
(1) 1/c < 1/b < 1/a
(2) c >a
(1) 1/c < 1/b < 1/a
(2) c >a
Can some one explain why we cannot do the following
1/c<1/b<1/a = c>b>a by taking reciprocals??
1/c<1/b<1/a = c>b>a by taking reciprocals??
Here's my take-
Firstly, abc != 0 => none of them = 0. They could be any other number, positive or negative.
Secondly, by taking a quick look the statements, I know the concept of inequalities and reciprocals and positives/negatives is being tested here.
I begin by statement 2 because it seems pretty straightforward: c > a. => nothing about b. NOT SUFFICIENT.
Then I come to statement 1: 1/c <1/b < 1/a . How can I deduce anything about the relationship among a, b and c? Well, there are a couple of rules:
Rule no. 1 - If x< y and x and y are both positive, then 1/x > 1/y .
Rule no. 2 - If x< y and x and y are both negative, then 1/x > 1/y .
The problem with statement 1 is that it doesn't tell me anything about the signs of a, b and c.
Case 1: What
...
Statistics : Posted by hdixit • on 04 Aug 2014, 18:40 • Replies 19 • Views 18666
