If n is the product of the 5 different prime numbers, how many factors n have except 1 and n?
n=a*b*c*d*e
where a,b,c,d and e are 5 different prime numbers.
No. of factors of n=(1+1)(1+1)(1+1)(1+1)(1+1)=32
Therefore, no. of factors except 1 and n = 32-2=30
Hence D
n=a*b*c*d*e
where a,b,c,d and e are 5 different prime numbers.
No. of factors of n=(1+1)(1+1)(1+1)(1+1)(1+1)=32
Therefore, no. of factors except 1 and n = 32-2=30
Hence D
Statistics : Posted by Paras96 • on 29 Aug 2023, 08:00 • Replies 3 • Views 119
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