Bunuel wrote:
When positive integer n is divided by 3, the remainder is 2. When n is divided by 7, the remainder is 5. How many values less than 100 can n take?
(A) 0
(B) 2
(C) 3
(D) 4
(E) 5
Kudos for a correct solution.
lowest possible value of n=5
interval between successive values of n=product of divisors 3 and 7=21
let x=additional possible values of n
5+21x<100
x<4.5
1+4=5 possible values of n<100
E
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