A + B = 5, B + C = 4, and C + D = 6, then AB + CD + AC + BD
Adding all three equations
=>A+2B+2C+D=15
=>A+D+2(B+C)=15
=>A+D=15-8=7
AB + CD + AC + BD
=>AB+AC+CD+BD
=>A(B+C)+D(B+C)
=>(A+D)(B+C)
=>7*4=28
Hence D
Adding all three equations
=>A+2B+2C+D=15
=>A+D+2(B+C)=15
=>A+D=15-8=7
AB + CD + AC + BD
=>AB+AC+CD+BD
=>A(B+C)+D(B+C)
=>(A+D)(B+C)
=>7*4=28
Hence D
Statistics : Posted by Paras96 • on 01 Nov 2021, 04:15 • Replies 8 • Views 1522
