Kinshook wrote:
Bunuel wrote:
If k is a negative constant and x is a variable, what is the value of k if one of the roots of the equation k(x - 1)^2 = 5x - 7 is double the other?
A. -1
B. -2
C. -3
D. -5
E.-25
A. -1
B. -2
C. -3
D. -5
E.-25
Asked: If k is a negative constant and x is a variable, what is the value of k if one of the roots of the equation k(x - 1)^2 = 5x - 7 is double theother?
\( k(x - 1)^2 = 5x -7\)
\( k(x^2 - 2x + 1) = kx^2 - 2kx + k = 5x-7\)
\( kx^2 - (2k+5) + k+7 =0\)
Let the roots of the equation be r and2r
\( r + 2r = 3r = (2k + 5)/k;\)
\( r =(2k+5)/3k\) (1)
\( 2r^2 = (k+7)/k\)
\( r^2 =(k+7)/2k\) (2)
\( (k+ 7)/2k =(2k+5)^2/9k^2\)
\( 9k^2(k+7) = 2k(2k+5)^2 = 2k(4k^2 + 20k + 25) =8k^3+40k+50\)
\( 9k^3 + 63k^2 =8k^3+40k+50k\)
\( k^3 + 23k^2 - 50k =0\)
k(k+25)(k-2)=0
k = -25; since k is a negative integer
IMOE
Why is 2k+5 divided by k? Similarly, why is k+7 divided by 2k?
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Statistics : Posted by erwr43534 • on 23 Jun 2020, 10:38 • Replies 8 • Views 2174