Data Sufficiency (DS) | Re: What is the value of (21*x^2*y)(5*y^2*x)?

The given fraction reduces to:
\(\frac{21x}{5y}\)
We need to find a value of x/y.

1) \(x^2y^2=16\)
Many possible cases.
Consider x=4, y=1 or the inverse case of y=4, x=1. Both yield different values.

2) similar case here. Both have many combinations

3)
knowing that x+y=5
x=5-y
\((5-y)^2y^2=16\)
A possible solution is y=1, x=4
However, because we do not know which of the values of x or y is larger, we cannot exclude the inverse case of x=1, y=4.

INS.

Statistics : Posted by mysterymanrog • on 23 Jan 2016, 07:37 • Replies 4 • Views 5974

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