Bunuel wrote:
What is the value of\( (\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} -\sqrt{10})\) ?
A. -4
B. -2
C. -1
D. 1
E.2
Fresh GMAT Club Tests'Question
OfficialSolution:
What is the value of\( (\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} -\sqrt{10})\) ?
A.\(-4\)
B.\(-2\)
C.\(-1\)
D.\(1\)
E.\(2\)
We want to find the value of the expression\( (\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} -\sqrt{10})\) . To simplify this expression, we can start by squaringit.
- \( =((\sqrt{4-\sqrt{15}})(4 + \sqrt{15})(\sqrt{6} -\sqrt{10}))^2=\)
\( =(4-\sqrt{15})(4 + \sqrt{15})^2(\sqrt{6} -\sqrt{10})^2=\)
\( =(4-\sqrt{15})(4 + \sqrt{15})(4 + \sqrt{15})(\sqrt{6} -\sqrt{10})^2=\)
Applying the difference of squares identity\( (a -b)(a+b)=a^2-b^2\) to\( (4-\sqrt{15})(4 +\sqrt{15})\) we can simplifyto:
- \( =(16 -15)(4 + \sqrt{15})(\sqrt{6} -\sqrt{10})^2=\)
Now using the identity\( (a -b)^2=a^2-2ab+b^2\) to simplify the squaredterm::
- \( =(4 + \sqrt{15})(6 -2\sqrt{60}+10)=\)
\( =(4 + \sqrt{15})(16 -4\sqrt{15})=\)
\( =(4 + \sqrt{15})4(4 -\sqrt{15})=\)
...
Statistics : Posted by Bunuel • on 04 Sep 2022, 09:35 • Replies 2 • Views 1032









