AnujL wrote:
gmatphobia
egmat
Bunuel
please suggest what is wrong with myapproach
median * number of terms = sum ofterms
20*10=200
x be the first term and x+20 be the final term
in order to have x+20 maximum ,we take all other 9 terms minimum.
x+x+x+x+x+x+x+x+x+x+20=200
10x+20=200
x=180/10=18
maximum term18+20=38
It should be (average)*(number of terms) = (sum ofterms) . And only when (average) =(median) (for example when the data set is evenly spaced) it will be the way you've written. Note that (average) =(median) does not necessarily mean that the data set is evenly spaced, for example, in {-3, 2, 2, 7} (average) = (median) =2 but the set is not evenlyspaced.
Set X consists of 10 integers and has the median of 20 and the range of 20. What is the value of the greatest possible integer that can be present in theset?
(A) 32
(B) 37
(C) 40
(D) 43
(E) 50
The range of 20 means that if the smallest term is x, then the largest term is x + 20. In ascending order the data set willbe:
[size=150]
...
Statistics : Posted by Bunuel • on 18 Jan 2023, 09:15 • Replies 4 • Views 421
