Bunuel wrote:
The lunch menu at a certain restaurant contains 4 different entrees and 5 different side dishes. If a meal consists of 1 entree and 2 different side dishes, how many different meal combinations could be chosen from this menu?
(A) 10
(B) 20
(C) 40
(D) 80
(E) 100
The number of combinations is 4C1 x 5C2 = 4 x (5 x 4)/2! = 4 x 10 = 40
Answer: C
Statistics : Posted by ScottTargetTestPrep • on 14 Oct 2019, 07:13 • Replies 6 • Views 4906






