If A, B and n are positive integers, is (3A+B)^n even
(3A+B)^n = ( OddXA+B)^n here we can omit the power n as (Odd)^n = Odd number and (Even)^n = Even number
Having said that,
(OddXA+B) may be solved in multiple cases
Case-1 A Odd B Odd
( OddXOdd+Odd)
(Odd+Odd)= even
Case-2 A Even B Odd
( OddXEven+Odd)
( Even+Odd)= Odd
Case-3 A Odd B Even
( OddXOdd+Even)
( Odd+Even)= Odd
Case-4 A Even B Even
( OddXEven+Even)
( Even+Even)= Even
Statement-1
A can be expressed in the form 8k+1, This means A is an Odd number but we do not know about B hence we cannot get an answer her eliminate A/D
Statement-2
7B is an Odd number, B is an odd number, but we cannot say anything about A, eliminate this answer.
Combining both statement we get A is odd and B is odd and this falls under case-1,
We can confidently say that answer is Yes (3A+b)^n is even
Answer C
(3A+B)^n = ( OddXA+B)^n here we can omit the power n as (Odd)^n = Odd number and (Even)^n = Even number
Having said that,
(OddXA+B) may be solved in multiple cases
Case-1 A Odd B Odd
( OddXOdd+Odd)
(Odd+Odd)= even
Case-2 A Even B Odd
( OddXEven+Odd)
( Even+Odd)= Odd
Case-3 A Odd B Even
( OddXOdd+Even)
( Odd+Even)= Odd
Case-4 A Even B Even
( OddXEven+Even)
( Even+Even)= Even
Statement-1
A can be expressed in the form 8k+1, This means A is an Odd number but we do not know about B hence we cannot get an answer her eliminate A/D
Statement-2
7B is an Odd number, B is an odd number, but we cannot say anything about A, eliminate this answer.
Combining both statement we get A is odd and B is odd and this falls under case-1,
We can confidently say that answer is Yes (3A+b)^n is even
Answer C
Statistics : Posted by RohitKakkar • on 23 Jan 2023, 09:15 • Replies 2 • Views 81










