Bunuel KarishmaB chetan2u
What if we start by first selecting 1 person from each of the married couples.
2C1 * 2C1 * 2C1 * 2C1 * 2C1 = 32
And then from these 5 people we can select any 3
5C3 = 10
I know this is definitely wrong as total number of ways can only be 10C3 = 120, but I what to know what am I missing ?
What if we start by first selecting 1 person from each of the married couples.
2C1 * 2C1 * 2C1 * 2C1 * 2C1 = 32
And then from these 5 people we can select any 3
5C3 = 10
I know this is definitely wrong as total number of ways can only be 10C3 = 120, but I what to know what am I missing ?
Statistics : Posted by SD0715 • on 05 Jan 2010, 06:46 • Replies 44 • Views 120603








