Problem Solving (PS) | Re: Rahul takes a solution which contains 100 percent pure water and repla

Solution:

• Water is 100 percent in the solution and 40% is taken out 3times
• This means final volume of water\(=100(1-\frac{40}{100})^3\)
  \(⇒100(\frac{60}{100})^3\)
  \( ⇒100\times \frac{6\times 6\times6}{1000}\)
  \(⇒21.6\)
• Amount of soda\(=100-21.6=78.4\)
• Ratio\(=\frac{78.4}{21.6}=\frac{98}{27}\)

Hence the right answer is OptionB
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Statistics : Posted by SaquibHGMATWhiz • on 24 Sep 2022, 04:43 • Replies 4 • Views 666

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