\(4x^2 – y^2 +4x + 4y – 3 = 0\)
\(4x^2 – y^2\)....\(x^2\) and \(y^2\) will be always positive
so , \(4x^2 – y^2\) will be positive.
Now to become whole equation = 0 , This part must be negative 4x + 4y – 3
So, y must be negative,
Option D
\(4x^2 – y^2\)....\(x^2\) and \(y^2\) will be always positive
so , \(4x^2 – y^2\) will be positive.
Now to become whole equation = 0 , This part must be negative 4x + 4y – 3
So, y must be negative,
Option D
Statistics : Posted by kapil1995 • on 04 Nov 2022, 00:30 • Replies 2 • Views 49








