Given that The three solutions of the equation \(f(x)=0\) are −2, 0 and 3. And we need to find the three solutions of the equation \(f(x−2)=0\)
There are three solution for f(x): -2, 0 and 3
=> f(x) = (x - (-2)) (x-0) (x-3) or some power of these terms
=> f(x) = x(x + 2)(x-3)
=> To find f(x-2) we need to replace x with x-2 in f(x)
=> f(x-2) = (x-2)(x-2 + 2)(x-2 - 3) = 0
=> (x-2)x(x-5)
=> x = 0, 2, 5
So, Answer will be D
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
Iframe
There are three solution for f(x): -2, 0 and 3
=> f(x) = (x - (-2)) (x-0) (x-3) or some power of these terms
=> f(x) = x(x + 2)(x-3)
=> To find f(x-2) we need to replace x with x-2 in f(x)
=> f(x-2) = (x-2)(x-2 + 2)(x-2 - 3) = 0
=> (x-2)x(x-5)
=> x = 0, 2, 5
So, Answer will be D
Hope it helps!
Watch the following video to learn the Basics of Functions and Custom Characters
Iframe
Statistics : Posted by BrushMyQuant • on 23 Sep 2021, 22:26 • Replies 2 • Views 936






