WholeLottaLove wrote:
If y >= 0, What is the value ofx?
(1) |x-3| >= y
We are told that |x-3| ≥ y but all we know is that y is a positive # greater than or equal to zero. Therefore, all we know is that |x-3| is greater than or equal to zero and x could be an infinite number of possibilities.
(2) |x-3| <= -y
(I am having real difficulty understanding the rationale for (2) could someone explain it to me? (preferably like they would to a 5th grader
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