Hello,
I noticed I solved this problem without multiplying the fractions into the total number of passengers:
So\((\frac{1}{10} ∗4)+(\frac{1}{4}∗2)+(\frac{1}{5}∗3)=\frac{4}{10} +\frac{ 2}{4} +\frac{ 3}{5} = 2/5 + 1/2 + 3/5 = 5/5 + 1/2 =1.5\)
So, Avg luggage per passenger will be 1.5 answer (A) still. Is there a downside to this approach?
...
I noticed I solved this problem without multiplying the fractions into the total number of passengers:
So\((\frac{1}{10} ∗4)+(\frac{1}{4}∗2)+(\frac{1}{5}∗3)=\frac{4}{10} +\frac{ 2}{4} +\frac{ 3}{5} = 2/5 + 1/2 + 3/5 = 5/5 + 1/2 =1.5\)
So, Avg luggage per passenger will be 1.5 answer (A) still. Is there a downside to this approach?
...









