Problem Solving (PS) | Re: If x is an integer and (x^2 - 2)!/(x^2-2)=33!, what is the rang

We can have 34 in the denominator, so that equation transforms to

\(\frac{34! }{ 34} = 33 !\)

\(x^2 - 2\) = 34

\(x^2 = 36\)

x = +6/ -6

Set of possible values of x = {-6,6}

Range = 12

Option E

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