Let's assume that C does 1 unit of work each day.
Thus B does 3 unit of work each day (as B is thrice as efficient as C)
A does 6 units of work each day (as A is twice as efficient as B)
Together they do 10 units of work each day.
We are also given that the work takes 10 days to complete, hence the volume of work is of 100 units.
Number of days A and B will take when they work together =\(\frac{ 100}{9}\)
Number of days B and C will take when they work together =\(\frac{ 100}{4}\)
Difference =[m]\frac{100}{4}
...
Thus B does 3 unit of work each day (as B is thrice as efficient as C)
A does 6 units of work each day (as A is twice as efficient as B)
Together they do 10 units of work each day.
We are also given that the work takes 10 days to complete, hence the volume of work is of 100 units.
Number of days A and B will take when they work together =\(\frac{ 100}{9}\)
Number of days B and C will take when they work together =\(\frac{ 100}{4}\)
Difference =[m]\frac{100}{4}
...







