Say farmer has n chicken and he is good for d days.:-
We have 3 equations given in question:-
(n-75) * d+20 =(n+100) *(d-15) = n * d
Solving these: (You can solve 1st and 3rd and 2nd and 3rd together)
We get:
20d-3n=300
4n-15d =75*4
=> n=300
We have 3 equations given in question:-
(n-75) * d+20 =(n+100) *(d-15) = n * d
Solving these: (You can solve 1st and 3rd and 2nd and 3rd together)
We get:
20d-3n=300
4n-15d =75*4
=> n=300
