Given that\( h(x) = 2x -1\) and\( g(x) = x^2 -3\) and\( g(m) =61\) and we need to find the value of\(h(m)\) if\( m >0\)
To find g(m) we need to compare what is inside the bracket () in g(m) and g(x)
=> We need to substitute x with m in\( g(x) = x^2 -3\) to get the value of g(m)
=>\( g(m) = m^2 -3\) = 61 (given)
=>\(m^2\) = 61 + 3 = 64 =\(8^2\)
=> m = 8
Similarly, h(m) = 2*m - 1 = 2*8 - 1 = 16 - 1 = 15
So, Answer will beD
Hope ithelps!
Watch the following video to learn the Basics of Functions
...
To find g(m) we need to compare what is inside the bracket () in g(m) and g(x)
=> We need to substitute x with m in\( g(x) = x^2 -3\) to get the value of g(m)
=>\( g(m) = m^2 -3\) = 61 (given)
=>\(m^2\) = 61 + 3 = 64 =\(8^2\)
=> m = 8
Similarly, h(m) = 2*m - 1 = 2*8 - 1 = 16 - 1 = 15
So, Answer will beD
Hope ithelps!
Watch the following video to learn the Basics of Functions
...
