Solution:
scholarships = students
1] 6 scholarships given, so 6 students given the scholarship, 4 not given
10C6 X (6!/x!y!z!)
10C6 --> selecting 6 from 10 students to give the money
6! --> we are looking at arranging the scholarships (1 for each student)
x,y,z = we know scholarships are of a certain kind - 3 types --> so we need to divide 6! by these
Since we dont know x,y,z --> not suff
2] 10Cn X (n!/x!y!z!)
not sufficient
Together] 10C6 X (6!/2!2!2!)
Ans - C
scholarships = students
1] 6 scholarships given, so 6 students given the scholarship, 4 not given
10C6 X (6!/x!y!z!)
10C6 --> selecting 6 from 10 students to give the money
6! --> we are looking at arranging the scholarships (1 for each student)
x,y,z = we know scholarships are of a certain kind - 3 types --> so we need to divide 6! by these
Since we dont know x,y,z --> not suff
2] 10Cn X (n!/x!y!z!)
not sufficient
Together] 10C6 X (6!/2!2!2!)
Ans - C









