Bunuel wrote:
v, w, x, y, and z are integers and v < w < x < y < z. What is the least possible value of the median of the foregoing set, if the mean is 48 and z = 62 ?
A. 30
B. 37
C. 38
D. 39
E.40
To minimise x, that is the median, maximise the remaining.
If z=62, the max value of y will be 61.
Also, the max value of w and v will be x-1 and x-2.
Thus,\(x-2+x-1+x+61+62=48*5\)
\(3x=120\)
\(x=4\)
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