Using concept of similar triangles,
Area (small triangle) / Area (larger triangle) = (1/2) ^ 2 (since height of larger triangle is twice of smallertriangle)
Thus, Area (small triangle) = 1 m
Area (larger triangle) = 4 m
Area (balance polygon) = 4 m - 1 m = 3m
Hence, Areas of triangles (smallest to largest) = 1m, 4m, 9m, 16m, 25m, 36m, 49m, 64m, 81m
Area of 8 portions of largest triangle (top to bottom) = 1m, 3m, 5m, 7m, 9m, 11m, 13m,15m,17m
Given, Sum
...
Area (small triangle) / Area (larger triangle) = (1/2) ^ 2 (since height of larger triangle is twice of smallertriangle)
Thus, Area (small triangle) = 1 m
Area (larger triangle) = 4 m
Area (balance polygon) = 4 m - 1 m = 3m
Hence, Areas of triangles (smallest to largest) = 1m, 4m, 9m, 16m, 25m, 36m, 49m, 64m, 81m
Area of 8 portions of largest triangle (top to bottom) = 1m, 3m, 5m, 7m, 9m, 11m, 13m,15m,17m
Given, Sum
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