Alternative approach from a units standpoint.
An area with dimension L^2 where L is the dimension of length has both added and subtracted from it the dimension of length, so only the lengths can be combined to maintain integrity of the dimensions.
Yet the result is 4, with dimension unstated.
The only dimension it could be is L^2, area, since no area was subtracted.
So the length dimension must be 2, theradius.
Posted from my mobiledevice
...
An area with dimension L^2 where L is the dimension of length has both added and subtracted from it the dimension of length, so only the lengths can be combined to maintain integrity of the dimensions.
Yet the result is 4, with dimension unstated.
The only dimension it could be is L^2, area, since no area was subtracted.
So the length dimension must be 2, theradius.
Posted from my mobiledevice
...
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