Let 'O', 'I', 'II', 'III' be the number of students who play zero, one, two and three games respectively.
Now, O = 18
The total number of students playing at least one game is given as follows:
I + II + III = 50 - 18 = 32
Now, those who play two games contribute to the total number of games played by 2 units, similarly, those who play three games contribute by 3. Hence,
I + 2 II + 3 III = 20 + 15 + 11 = 46
Subtracting these equations we get
II + 2 III = 14
Consider the second statement.
7 play
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Now, O = 18
The total number of students playing at least one game is given as follows:
I + II + III = 50 - 18 = 32
Now, those who play two games contribute to the total number of games played by 2 units, similarly, those who play three games contribute by 3. Hence,
I + 2 II + 3 III = 20 + 15 + 11 = 46
Subtracting these equations we get
II + 2 III = 14
Consider the second statement.
7 play
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