Given that\( g(x) = ax^2– 3x –b\) and g(5) = 0, and g(–2) = 0 and we need to find the value ofab
Let's start with g(5).
To find value of g(5) we need to substitute x=5 in\( g(x) = ax^2– 3x –b\)
=>\( g(5) = a*5^2– 3*5 –b\) = 25a - 15 - b = 0 (given)
=> 25a - b = 15 .... (1)
Similarly, let's find the value of g(-2)
To find value of g(-2) we need to substitute x=-2 in\( g(x) = ax^2– 3x –b\)
=>\( g(-2) = a*(-2)^2– 3*(-2) –b\) = 4a +6 - b = 0 (given)
=> 4a - b = -6 .... (2)
(1)
...
Let's start with g(5).
To find value of g(5) we need to substitute x=5 in\( g(x) = ax^2– 3x –b\)
=>\( g(5) = a*5^2– 3*5 –b\) = 25a - 15 - b = 0 (given)
=> 25a - b = 15 .... (1)
Similarly, let's find the value of g(-2)
To find value of g(-2) we need to substitute x=-2 in\( g(x) = ax^2– 3x –b\)
=>\( g(-2) = a*(-2)^2– 3*(-2) –b\) = 4a +6 - b = 0 (given)
=> 4a - b = -6 .... (2)
(1)
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