SajjadAhmad wrote:
\(x\) is how many times of\(y\) if\( y ≠0\) ?
(1)\(\frac{x}{y} +\frac{ y}{x -2y} =0\)
(2)\( x =\frac{ 2y}{x +y}\)
Source: NovaGMAT
Asked:\(x\) is how many times of\(y\) if\( y ≠0\) ?
(1)\(\frac{x}{y} +\frac{ y}{x -2y} =0\)
\(\frac{x}{y} +\frac{ y}{x -2y} =0\)
\(\frac{ x(x-2y) +y^2}{y(x-2y)} =0\)
\(\frac{ (x^2 - 2xy +y^2)}{y(x-2y)} =0\)
\(\frac{(x-y)^2}{y(x-2y)} =0\)
x = y
SUFFICIENT
(2)\( x =\frac{ 2y}{x +y}\)
x(x+y) = 2y
x^2 + xy - 2y = 0
y = x^2/(2-x)
NOT SUFFICIENT
IMO A
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