st1
x-1 = +/- 2(x-1)
(when +) x= 3
(when -) x=1/3
two values insufficient
st 2 tells us x cant be three. Alone this info is insufficient
combined we know x=1/3 hence sufficient.
x-1 = +/- 2(x-1)
(when +) x= 3
(when -) x=1/3
two values insufficient
st 2 tells us x cant be three. Alone this info is insufficient
combined we know x=1/3 hence sufficient.