If x2+5z+2xy+6=2xyx2+5z+2xy+6=2xy and x≠–2x≠–2, what is the value of x ?
(1) y=1
After putting values we get
x² + 5z + 6 = 0
2 variables 1 equation, Not sufficient :
(2) z=x
2xy in LHS and RHS get cancelled, we get.
x² + 5z + 6 = 0
we get: x² + 5x + 6 = 0
(x+3) (x+2)
We get 2 solution, x= -2, x= -3,
As -2 cannot be solution we are left with 1 solution, X=-3
Sufficient
IMO B
(1) y=1
After putting values we get
x² + 5z + 6 = 0
2 variables 1 equation, Not sufficient :
(2) z=x
2xy in LHS and RHS get cancelled, we get.
x² + 5z + 6 = 0
we get: x² + 5x + 6 = 0
(x+3) (x+2)
We get 2 solution, x= -2, x= -3,
As -2 cannot be solution we are left with 1 solution, X=-3
Sufficient
IMO B
