emmak wrote:
If 73! has 16 zeroes at the end, how many zeroes will 80! have at the end?
A. 16
B. 17
C. 18
D. 19
E. 20
\(\frac{80}{5} = 16\)
\(\frac{16}{5} = 3\)
Hence total number of zeroes will 80! have is 19 , Answer must be (D)
If 73! has 16 zeroes at the end, how many zeroes will 80! have at the end?
A. 16
B. 17
C. 18
D. 19
E. 20
\(\frac{80}{5} = 16\)
\(\frac{16}{5} = 3\)
Hence total number of zeroes will 80! have is 19 , Answer must be (D)
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