dave13 wrote:
GMATWhizTeam wrote:
Bunuel wrote:
For a sequence\(t_1\) ,\(t_2\) ,\(t_3\) , ...,\(S_n\) denotes the sum of the first n terms of a sequence. If\( S_n = n^3 + n^2 + n +1\) , and\( t_m =291\) , then m is equal to?
A. 20
B. 22
C. 24
D. 26
E.30
A. 20
B. 22
C. 24
D. 26
E.30
Solution
- •\( S_n = n^3 + n^2 + n+1 = n^2(n + 1) + 1(n +1) = (n+1)(n^2 +1)\)
•\( t_m =291\)
•We need to find the value of m.
•Now,\( t_m = S_m – S_{m-1} = (m +1 )(m^2 + 1) – (m-1+1)((m-1)^2 +1)\)
- o\( ⟹t_m = m^3 +m^2 +m+1 – m(m^2 -2m + 2)\)
o\( ⟹t_m = m^3 + m^2 +m+1 – m^3 +2m^2 –2m\)
o[m] ⟹ t_m
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