[quote="devinawilliam83"]Is x|y| > y^2?
(1) x > y
(2) y > 0
[spoiler=]I rephrased the question as x|y|>|y| (since y^= |y|. On solving this I rephrased as x>1?
target Is x|y| > y^2 yes and no type DS
#1
x > y
test with x= 2 & y = 1
we get yes to x|y| > y^2
and x=2 and y = -3
we get no to x|y| > y^2
insufficient
from 2
y>0
no info about x
insufficient
from 1 &2 x|y| > y^2 would be sufficient
OPTION B
(1) x > y
(2) y > 0
[spoiler=]I rephrased the question as x|y|>|y| (since y^= |y|. On solving this I rephrased as x>1?
target Is x|y| > y^2 yes and no type DS
#1
x > y
test with x= 2 & y = 1
we get yes to x|y| > y^2
and x=2 and y = -3
we get no to x|y| > y^2
insufficient
from 2
y>0
no info about x
insufficient
from 1 &2 x|y| > y^2 would be sufficient
OPTION B
