stne wrote:
Kritisood wrote:
In the figure given, O is the center of the circle, and the area of the triangle OPQ = 16√3. If ∠OPQ = 30 degrees, find the radius of the circle.
A. 4 cm
B. 5 cm
C. 6 cm
D. 8 cm
E. 10cm
A. 4 cm
B. 5 cm
C. 6 cm
D. 8 cm
E. 10cm
Attachment:
GMAT Club geometry.png
Let the radius be\(x\) and lets draw a perpendicular as shown in the figure.We now have two 30 60 90 Triangles.
So the sides are as shown in the figure.
We know the area of\( \Delta\) OPQ =\( \frac{1}{2} 2x\sqrt{3}*\frac{x}{2}=16\sqrt{3}\)
\( x^2=64\)
\( x=8\)
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