If k is a positive integer, what is the remainder when (k + 2)(k^3 – k) is divided by 6 ?
(k+2)(k^3–k)
=(k+2)k(k^2–1)
=(k+2)k(k–1)(k+1)
=(k−1)k(k+1)(k+2)
now, we know, the product of 3 consecutive numbers is always divisible by 6.
so, (k+2)(k^3–k) is divisible by 6.
the remainder when (k + 2)(k^3 – k) is divided by 6 = 0
correct answer A
(k+2)(k^3–k)
=(k+2)k(k^2–1)
=(k+2)k(k–1)(k+1)
=(k−1)k(k+1)(k+2)
now, we know, the product of 3 consecutive numbers is always divisible by 6.
so, (k+2)(k^3–k) is divisible by 6.
the remainder when (k + 2)(k^3 – k) is divided by 6 = 0
correct answer A








