[quote="ScottTargetTestPrep"][quote="Bunuel"] There are six cards bearing numbers 2, 4, 5, 5, 5, 6. If two cards are randomly selected from the lot, what is the probability that the positive difference between the numbers on these cards is 3 or less?
A.[m]\frac{8}{15}[/m]
B.[m]\frac{9}{15}[/m]
C.[m]\frac{10}{15}[/m]
D.[m]\frac{12}{15}[/m]
E.[m]\frac{14}{15}[/m]
M11-08[/quote]
We see that there are 6C2 = (6 x 5)/2 = 15 ways to choose two numbers from six numbers, and the only way that the difference between two chosen numbers is not 3 or less (i.e., a difference
...
A.[m]\frac{8}{15}[/m]
B.[m]\frac{9}{15}[/m]
C.[m]\frac{10}{15}[/m]
D.[m]\frac{12}{15}[/m]
E.[m]\frac{14}{15}[/m]
M11-08[/quote]
We see that there are 6C2 = (6 x 5)/2 = 15 ways to choose two numbers from six numbers, and the only way that the difference between two chosen numbers is not 3 or less (i.e., a difference
...
