parkhydel wrote:
The average (arithmetic mean) of the positive integers x, y, and z is 3. If x < y < z, what is the greatest possible value of z?
A. 5
B. 6
C. 7
D. 8
E. 9
PS00986
Given: The average (arithmetic mean) of the positive integers x, y, and z is 3.
Asked: If x < y < z, what is the greatest possible value of z ?
x + y + z = 9 & x < y < z
For z to be greatest, x & y have to be least.
Since x, y & z are positive integers
x = 1; y = 2; z = 6
IMO B
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